Tuesday, September 18, 2012

Line Segment Chart


Introduction to line segment chart

A line chart or line graph is a type of graph, which displays information as a series of data points connected by straight line segments. It is a basic type of chart common in many fields. It is an extension of a scatter graph, and is created by connecting a series of points that represent individual measurements with line segments (Source: Wikipedia)

Line Segments Chart

Line segments is a division of a line to be surrounded through two finish points. Line contains each point lying on the line among its finish points. Instance of line segments contain the faces of a triangle otherwise square. More usually, while the finish points are equally vertices of a polygon, the line part is any an edging if they are diagonal.

A line chart is over also over again utilized to imagine a development within data in excess of intervals of time; therefore the line is frequently haggard chronologically.Within the experimental sciences, data composed as of testing are frequently imagine through a graph to include an overlay arithmetical meaning representing the finest fit trend of the sprinkled data graph.

For instance, if one were to accumulate data lying on the speed of a body on assured points within time, one could visualize the data:

Example for Line graph

Time: 0 1 2 3 4 5

Speed: 0 4 8 12 14

Time can be represented within x-axis.

Time can be represented within y-axis.


Examples for Line Segment

Example 1

Within a line segment one endpoint is (-2, 6) also the midpoint of the line is (- 6, 10). Compute the co-ordinates of the other endpoint are (x1, y1).

Solution:

`(-6,10)=((x_(1)+(-2))/2),(y_(1)+6)/2`

To find for x1,

`-6=((x_(1)+(-2))/2)`

-12= x1-2

-10 = x1

To compute for x2,

`10=((x_(2)+(6))/2)`

20 = y1 + 6

Y1 = 14

So, the next endpoint of the line is (-10, 14)


Example 2

Within a line segment one endpoint is (-4, 8) also the midpoint of the line is (- 6, 8). Compute the co-ordinates of the other endpoint are (x1, y1).

Solution:

`(-6,8)=((x_(1)+(-4))/2),(y_(1)+8)/2`

To compute for x1,

`-6=((x_(1)+(-4))/2)`

-12= x1-4

-8 = x1

To solve for x2,

`8=((x_(2)+(8))/2)`

16 = y1 + 8

y1 = 8

So, the next endpoint of the line is (-8, 8)

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