The Math Term for Conjecture

Introduction to math term conjecture:

The term conjecture in math refers a statement or assumptions that are not proved. It is like a theorem, but they have not proved. For example the kite area conjecture states that the area of kite is equal to half the product lengths of two diagonals. The term Conjecture can be also mean as rules or conditions. In this article we shall some math conjectures and example problems.

Math Term for Conjecture – Formulas:

Rectangle area conjecture:

Area of rectangle (A) = b x h square units

Where,

A – Area of rectangle

b – Length of the base

h – Height of the rectangle

Trapezoid area conjecture:

The diagram of trapezoid is shown in below.

Area of trapezoid (A) = `1/2` x h x (a + b) square units

Where,

A – Area of trapezoid

h – Height

a, b – length of two parallel sides

Circle area conjecture:

The diagram of circle is shown in below

Area of the circle (A) = pr2 square units

Where,

A – Area of circle

r – Radius of circle

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Math Term for Conjecture – Example Problems:

1. The rectangle has base length 10.5 cm and height 5.5 cm. solve for area of rectangle.

Solution:

Given:

Base Length (b) = 10.5 cm,

Height (h) = 5.5 cm

Solving area:

Rectangle area conjecture:

Area of rectangle = b x h square unit.

= 10.5 x 5.5

Area of rectangle = 57.75 cm^2

2.      Find the area of trapezoid whose height 13.5 cm, side a= 7.5 cm and side b= 9.5 cm

Solution:

Given:

Height (h) = 13.5 cm

Side a= 7.5 cm;            b= 9.5 cm

Formula:

Area of trapezoid (A) = `1/2` x h x (a + b) square units

=`1/2` x 13.5 x (7.5 + 9.5)

=`1/2` x 13.5 x 17

=`1/2` x 229.5

= `229.5 / 2`

= 114.75

Area of trapezoid (A) = 114.75 cm^2

3. The radius of a circle is 8.5 cm. Find the area of that circle?

Solution:

Given:

r = 8.5 cm

Formula:

Area of the circle = p x r^2

p = 3.14

A = 3.14 x (8.5)^2

=3.14 x 72.25

Area of circle = 226.86 cm^2

Definition of Exercise in Math

Introduction for Math Exercise:

Collection of practice problem is known as exercise. If a student wants some definition in math exercise with problems, they can refer to the below examples. In this we can see some of the math exercise in statistics with example problems as shown. Let us see some of the general math exercise in statistics such as mean, median and mode with examples and practice problems as follows.

Definition of Exercise in Math – Definitions for Exercise:

In this following we can see some math definition for statistics exercise.

Mean:

It is a set of data which can find the average in dividing by sum of numbers with total numbers in the given data.

Median:

It is a set of numbers which can find the middle numbers and arrange the numbers in order to select the middle number.

Mode:

It is a set of numbers that can occur frequently in a set of data and no number can occur more than once.

Definition of Exercise in Math – Examples and Practice Problems:

In this following we can see some math definition for statistics exercise with example and practice problems.

Math Definition for Exercise 1:

Find the mean of weights for 6 peoples in kilograms are 4, 1, 9, 2, 11, and 3.

Solution:

Sum of numbers
Mean = ------------------------------
Total number

= `(4+1+9+2+11+3)/6`

= `30/6`

= 5

Math Definition for Exercise 2:

Find the median of 16, 1, 15, 13, 20, and 8.

Solution:

Arrange the data in ascending order as 1, 8, 13, 15, 16 and 20.

N = 6

Since n is even, median = `1 / 2` [`(nth)/2` item value + (`n / 2` + 1)th item value]

= `1 / 2` [6th item value + (`6/2` + 1)th item value]

= `1 / 2` [3rd item value + 4th item value]

= `1 / 2` [13 + 15]

= `1 / 2` * 28

= 14

Math Definition for Exercise 3:

Find the mode of 23, 19, 28, 13, and 28.

Solution:

28 are repeated twice.

Mode = 28

Practice Problems:

Find the mean of weights for 6 peoples in kilograms are 8, 1, 10, 2, 7, and 3.

Solution:

= 5.16

Find the median of 19, 14, 6, 8, 3, and 12.

Solution:

= 10

Find the mode of 17, 19, 16, 24, and 19.

Solution:

= 19

Statistical Test for Ordinal Data

Introduction to Statistical test for ordinal data

Ordinal data:

Ordinal data is described the counting of the data which is using the natural “order”. Let us take an example in bike race we decide the prizes for the winner by means of the ranking order such as consider 1st, 2nd and 3rd. And if we would like to measure whatever thing we will use ordinal data scale. The selection of Statistical Analysis: These methods explain the association between the response variable and one or more explanatory variables. We are having binary responses like “yes” or “no”, “male or female”, or “success or failure” etc. Understanding Statistical Median is always challenging for me but thanks to all math help websites to help me out.

Study about Statistical Test for Ordinal Data

‘Statistical analysis’, a categorical ordinal data research suggest is one which used for definite scale measurement. Here categorize categorical ordinal data and continuous data. This is used to measure ‘explanatory variable’ and a ‘response variable’.

Scale of Measurement in Statistical Test for Ordinal Data:

It consists of four types of scales appear in categorical data statistical analysis,

Nominal scales.
Ordinal scales.
Interval scales.
Ratio scales.
They are categorized into two groups in this analysis:

Categorical and
Continuous scale data.
Categorical data:

It contains nominal and ordinal scales data.

Continuous scale data:

It contains interval and ratio scales data.

An ordinal determines an “ORDERED SERIES”, such as graded responses to an item on a survey:

Ordinal scales:

Categorical data which having approved scales are known as an ordinal scale. Is this topic Chi Square Test Degrees of Freedom hard for you? Watch out for my coming posts.

Examples of Statistical Test for Ordinal Data

Example 1 – Statistical test for ordinal data:

Rank of student is one of an example of ordinal scale.

Example 2 – Statistical test for ordinal data:

Survey item:

“Sachin tendulkar will participate in the next worldcup”

For this suggestion shall we take the survey of 10 peoples which gives the result as

Response choices:

Agree = 2, Neither agree nor disagree = 3, Strongly agree = 4, Disagree = 1, Strongly disagree = 0.

Example 3 – Statistical test for ordinal data:

Statistical Methods:

Evocative statistics are used to examine the essential features of data under consideration.

Table is statistical method can be used to represent data sets with number of variables, e.g:

Annals of Applied Probability

Introduction to annals of applied probability:

The Annals of Applied Probability seek to publish research of the highest quality reproduce the different facets of current Applied Probability.  Most important emphasis is located on importance and originality. Probability is a system of expressing information or belief that an event will occur or has occurred. The application of probability is other technical and business domain. Conversely, while investigate is motivated by applied problems, it is usually the mathematical aspect of the problems that are of most importance to researchers I like to share this Statistics Probability with you all through my article.

Some Problems for Annals of Applied Probability:

Annals of applied probability problems 1:

In that color pencils there are 26 red color pencils, 37 blue color pencils and 60 yellow color pencils.

Evaluate the probability,

Select the red color pencils.

Select the blue color pencils.

Solution:

Totality color pencils n(S) = 124

Red color pencils n (A) = 27

Blue color pencils n (B) =37

Yellow color pencils n(C) = 60

P (A) is the probability for select yellow color pencils.

`P = (A) = (n(A))/(n(S))`

`= 27/124`

P (B) is the probability for select blue color pencils.

`P(B) =(n(B))/(n(S))`

= `37/124`

Annals of applied probability problems 2:

33 tokens numbered from 1 to 33, five tokens are drawn simultaneously. Find out the probability that:

a) Both the tokens drawn have prime number

b) None of the tokens drawn have a prime number

Solution:

We want to select 5 tokens from 33 tokens.

n(S) = 33C5

`= (33!) / (5! (33 - 5)!)`


`= 237,336`

a) Let A = Event that both the tokens have prime numbers.

Prime numbers “between” 1 to 33 are: 1, 3, 5, 7, 11, 13, 17, 19, 21, 23, 25, 27, 29 and 31

Total Numbers = 14.

We have to select 2 numbers from these 14 numbers.

n(A) = 14C5

`= (14!)/ (5! (14 - 5)!)`

`= 2,002`

`P(A)=(n(A)) / (n(S))`

`= (2,002)/(237,336)`

b) Non prime numbers between 1 to 33: 33 - 14 = 19

Let B = Event that both the tokens have non-prime numbers.

Now we have to select 2 numbers, from 19 numbers. Please express your views of this topic 2 digit subtraction with regrouping by commenting on blog

n(B) = 19C5

`= (19!)/ (5!(19 - 5)!)`

`= 11,628`

`P(B) = (n(B)) / (n(S))`

`=(11,628)/ (237,336)`

Practice Problem for Annals of Applied Probability:

In a pack of cards two cards where drawn at random. Find the chance that one is and king the other a queen.

Answer: `8/ 663`

In that color pencils there are 26 red color pencils, 37 blue color pencils and 50 yellow color pencils.

Answer: n (a) = `9/38 ` (b) = `37/114`

Different Ways to Multiply

Introduction to different ways to multiply:
In general, Process of multiply is an arithmetic operation. In mathematics sequence of notice the amount (product) get clasp of repeated totaling of a particular amount (multiplicand) a particular number of occasions (multiplier): represented in different methods. When a number (A) is multiplied by a particular number (S) it is nothing but the particular number (S) of times the number (A) should be repeated is shown in example.

Ex.: 4 xx 3 or 4 xx 3, it means 4 + 4 + 4= 12, to adding the integer five four times

Different Ways of Multiply:
There were two ways in multiply integers. They are given below,

General multiply method and,

By way of multiply through addition.

General multiply method: is done by multiplying through the given value. For example, 44 xx 3 is multiply by the ways of multiplying 44 into 3 is given the answer as 132. Thus the ways we perform the operation in general method.

Way of multiply through addition: is done by the repeated times of addition the multiplier is shown below for clear understanding. For example, 44 xx 3 is multiply by the ways of multiplying 44 into 3 is given the answer as 44 + 44 + 44 = 132. Thus the ways we perform the operation in multiply through addition method.Understanding rational numbers definition is always challenging for me but thanks to all math help websites to help me out.

Example for Different Ways of Multiply:

Problem: Show the different ways of multiply for `(22 xx 5)`

Solution:

First way: Solution: `22 xx 5` is done by two ways are,

General multiplication method:   22
5
110
Thus, the way of general multiplication is done.

Second way: Multiplication through addition is,

`22 xx 5 = 22 + 22 + 22 + 22 + 22`

`= 110`

Thus the second way is also done.

Thus, the different ways of multiply is explained.

Problem: Show the different ways of multiply for `(89 xx 6)`

Solution:

First way: `89 xx 6` is done by two ways are,

General multiplication method:   89
6
534
Thus, the way of general multiplication is done.

Second way: Multiplication through addition is,

`89 xx 6 = 89 + 89 + 89 + 89 + 89`

`= 534`

Thus the second way is also done.

Thus, the different ways of multiply is explained.

Value Added Calculation

Introduction to value added calculation:

In this article we shall discuss the value added calculation. Here, value added calculation is also meant by finding the total or sum by combining two or more numbers. Now simple example of value added calculation is 5 + 3 + 7 = 15. And simple example of decimal value added calculation is 1.456 + 2.647 + 0.42 = 4.523 I like to share this Summation Calculator with you all through my article.
Example Problems Based on Value Added Calculation:
The example problems based on value added calculation is shown given below that,

Example 1:

How do you learn value added calculation of following numbers are 55 + 85 + 35?

Solution:

Step 1:

The given value is 55 + 85 + 35.

Step 2:

First we have to add 55 + 85.

So, we can get the value for 55 + 85 = 140.

Step 3:

Now, we have to add 140 + 35.

So, we can get the value for 140 + 35 = 175.

Step 4:

The final answer for learn value added calculation is 175.

Example 2:

How do you learn value added calculation of following numbers are 700 + 875 + 682?

Solution:

Step 1:

The given value is 700 + 875 + 682.

Step 2:

First we have to add 700 + 875.

So, we can get the value for 700 + 875 = 1575.

Step 3:

Now, we have to add 1575 + 682.

So, we can get the value for 1575 + 682 = 2257.

Step 4:

The final answer for value added calculation is 2257.

Example 3:

How do you learn value added calculation of following numbers are 0.845 + 1.423 + 2.37?

Solution:

Step 1:

The given value is 0.845 + 1.423 + 2.37.

Step 2:

First we have to add 0.845 + 1.423.

So, we can get the value for 0.845 + 1.423 = 2.268

Step 3:

Now, we have to add 2.268 + 2.37

So, we can get the value for 2.268 + 2.37 = 4.638

Step 4:

The final answer for learn value added calculation is 4.638

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Practice Problems Based on Value Added Calculation:

The practice problems based on value added calculation is shown given below that,

Problem 1:

How do you learn value added calculation of following numbers are 567 + 98 + 83?

Answer:

The final answer for learn value added calculation is 748.

Problem 2:

How do you learn value added calculation of following numbers are 5.76 + 12.34 + 7.367 + 10.4?

Answer:

The final answer for learn value added calculation is 35.867

Four or more Terms Math

Introduction to four or more terms math:

The math is a learning of the quantity, space, structures and measurements, using numbers and symbols. All the way through the use of logical reasoning. The math terms are evolved from counting, computation, capacity. The math terms are including are, angle, graph, algebra, arc, area, square root, etc.

Four or more Terms Math:

In the four or more math terms, we will discuss about  square root,angle,algebra and set.

Square Root:

In math, the square root is a number r such that r2=x.
Any positive real number x have a same positive square root, this is known as principal square root.
In math term the square root is denoted by √x.
For positive x, the primary square root is able to as well write in exponent notation as x1/2.
For instance, the principal square root of 16 is four. It is denote by √16=four
For the reason that, 42=four*four=16 and four is non-negative.
Algebra:

The algebra is a one of the math term.
Then algebra is a one of the pure major branch of the mathematics.
It is involves the learning of rules of operations and relations and the meaning of polynomials and equations and the algebraic structure.
It is combining with the geometry and number theory.
The one of branch of algebra is known as elementary algebra.
Types of algebra:

Algebra has more than few  types. These are
Elementary algebra
Abstract algebra
Linear algebra
Universal algebra
Algebraic number theory
Algebraic geometry
Algebraic combinatorics.

Angle and Sets

Angle:

In math terms, an angle is a grouping of two rays with a general ending point.
The angle is used to measuring the how much bending or turning from one line to another line.
In geometry, the angles contain more than few types. These are,
Acute angle
Right angle
Obtuse Angle
Straight angle
Reflex angle
Acute angle:

This angle appears less than 90°.
Right angle:

This angle demonstrates at exactly 90°.
Obtuse Angle:

The Obtuse Angle is display at  larger than 90 but smaller than 180°.
Straight angle:

The straight angle is defines shows at exactly at 180°.
Reflex Angle:

The reflex angle is shows at the greater than 180°.
Sets:

A set is also one of the math terms.
A set is a collection of different more then objects.
The elements or member of a set can be everything like, numbers, letters, alphabets etc.

Time Formula Math

Introduction to time formula math:
In this section we will study about time formula math. Time formula math provide us to calculate the elapsed time for particular process. By using the simple time formula in math we can easily find out the starting time and ending time of any process. Let us study about time formula math.

Example Problems for Time Formula Math:

Example problem: On a hot summer day, Seth and his friends decided to have a water fight. They threw water balloons for 1 hour. When all the water balloons were gone, they sprayed water with hoses for 30 minutes. The water fight ended at 4:30 P.M. when Seth's dad showed up with ice cream. What time did the water fight start?

Solution:

Add the times to find the total elapsed time.

1 h + 30 min = 1 h 30 min

Now find 1 hour and 30 minutes before 4:30 P.M.

Count back by hours to find 1 hour before 4:30 P.M. This is 3:30 P.M.

Now subtract 30 minutes from 3:30 P.M. This is 3:00 P.M.

The water fight started at 3:00 P.M.

Answer: The water fight started at 3:00 P.M.Please express your views of this topic Standard Deviation Divided by Mean by commenting on blog.

Practice Problems for Time Formula Math:

Practice problem 1: Nate and his friends went to a movie on Saturday. They left the house at 2:00 P.M. It took 30 minutes to drive to the theater, and they arrived 30 minutes before the movie started. What time did the movie start?

Practice problem 2: Paige went to the mall with her mom. They started shopping at 3:30 P.M. First, they spent 1 hour in the shoe store. Then they spent 30 minutes shopping for a dress for Paige. Finally, they spent 30 minutes eating dinner at the food court. What time was it when Paige and her mom finished eating dinner?

Practice problem 3: Miranda started playing a video game at 8:30 A.M. It took her 2 hours to beat the first level and 1 hour to beat the second level. Miranda played the final level for 1 hour and 30 minutes and finished the game. What time was it when Miranda stopped playing the game?

Solutions for time formula math:

Solution 1: The movie started at 3:00 P.M.

Solution 2: It was 5:30 P.M. when Paige and her mom finished eating dinner.

Solution 3: It was 1:00 P.M. when Miranda stopped playing the game.