Monday, November 26, 2012

Elementary Math Tutorial


Introduction to elementary math tutorial:

The elementary math work consists of mathematics topics taught in the primary and secondary schools. The most important in elementary mathematics are arithmetic, geometry, algebra, number work and special functions. In secondary school the topics are trigonometry, Calculus etc. In elementary math tutorial, the basic operations and problems are clearly taught by the tutors with the examples solved in steps. Now we are going to see about elementary math tutorial.

About Elementary Math Tutorial:

Now we see the elementary mathematics with the help of the tutorial problems.

1. Number system:

The number system consists of the natural, decimal, fractional, rational numbers etc. Let us see one example for the rational number in number system.

Tutorial Example:

Find the fraction for the given decimal number 0.66

Solution:

The given decimal can be simplified as follows,

0.66 = 6 tenths + 6 hundredths

= 6 × `(1/10)` + 6 × `(1/100)`

= `(6/10)` + `(6/100)`

= `66/100`

= `33/50` .

2. Arithmetic:

In arithmetic, we can see about the housing finance, speed, time, distance, ratio etc.

Tutorial example:

Find the ratio of 5 Kg to 850 g

Solution:

The ratio can be determined and explained below

5 Kg = 5 × 1000 = 5000 g

The ratio can be given as

Required ratio = 5000: 850

= 500: 85

= 100: 17

Thus, the ratio is given as 100: 17

Other Elementary Math Tutorials:

1. Algebra:

Algebra is the part of mathematics where it consists of many expressions such as variables, constants and coefficients. Now we see an example

Tutorial example:

Determine and expand the given expression: (2a + 2b + 2c)2

Solution:

Let us take the equation with ( x + y + z)2

x = 2a, y = 2b, z = 2c

(2a + 2b + 2c)2 = (2a)2 + (2b)2 + (2c)2 + 2(4ab + 4ac + 4bc)

= 4a2 + 4b2 + 4c2 + 8ab + 8ac + 8bc

2. Geometry:

Geometry is about the learning of various size, shape and properties of the geometrical solid figures.

Tutorial example:

Find the diameter of the circle where the circumference of circle is about 8 cm.

Solution:

The circumference of the circle determined as follows,

C = π × d

8 = 3.14 × d

d = `8/3.14`

d = 3.18cm.

The diameter of the circle is determined as 2.54 cm.

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