Elementary Math Area

Introduction For elementary Math Area:

Elementary math area consist of area for square, rectangle ,triangle it is a menstruation part it is interesting in finding area of shapes and measuring length for given shapes. In menstruation area is an essential part for measuring the shape length. Measurement math consists also volume, surface area such as in higher grade for elementary math we have only fundamental shapes.

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Elementary Math Area For Square:


Area of a Square:
We know  square is a like rectangle in which its Length = Breadth.
The area of the square
= Length `xx ` Length
= (Length)2 = (Side)2
= a × a
= a^2

Example 1:
Find area of a square whose side is 12 cm.

Solution :
Side of the square, a = 12 cm
Area of the square, A = a^2
= a × a
= 12 × 12
= 144 sq.cm (or 144 cm2)
Example 2:
Find area of a square whose side is 14 cm.

Solution :
Side of the square, a = 14 cm
Area of the square, A = a^2
= a × a
= 14 × 14
= 196 sq.cm (or 196 cm2)

Area of Rectangle:
Length `xx` Breadth

Example 1 :
Length and breadth of a rectangle are 15 cms and 13 cms respectively. find its area.

Solution:
= Length `xx` Breadth
= l `xx` b
= 15 cm. `xx` 13 cm.
= 195 Sq. cm.

Example 2:
Find the area  of a rectangle whose length is 2m and breadth is 70 cm.

Solution :
Length of the rectangle, l = 2 m or 200 cm
Breadth of the rectangle, b = 70 cm
Area of the rectangle, A = l × b
= 200 cm × 70 cm
Area = 14000 sq.cm.

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Elementary Math Area For Triangle:


Area of a  triangle:
`1/2` × base × height

Example 1 :
In a triangle the length of sides containing  angles are 20 cm and 21 cm. Find its area.

Solution :
Let b = 20 cm and h = 21 cm
Area of the right triangle, A =1/2 bh
= `1/2` × 20 cm × 21 cm
= 210 sq.cm

Example 2 :
In a right triangle the length of sides containing the right angles are 15 cm and 20 cm. Find its area.

Solution :
Let b = 15 cm and h = 20cm
Area of the right triangle, A = `1/2` bh
=`1/2` × 15 cm × 20 cm
= 150 sq.cm