Showing posts with label elementary algebra. Show all posts
Showing posts with label elementary algebra. Show all posts

Tuesday, April 16, 2013

Rules for Elementary Algebra


Introduction to rules for elementary algebra:

Algebra is a system of written calculations that help us reason about numbers. At the very first, we should realize that algebra is a skill. The initial thing to note is that, in algebra, we use letters as well as numbers.  But the letters represent numbers.  And the rules of algebra match to the rules of arithmetic, but we write those rules using letters. Rules for elementary algebra is very basic in algebra, Now we are going to see about the rules for elementary algebra.

Please express your views of this topic Transitive Property of Equality by commenting on blog.

Rules for elementary algebra part - I:


Property of zero

0 · x = 0
0 + x = x

Property of One

1 + x = 1
1. x = x

Identity Property

x · x = x
x + x = x

Redundancy Property

x · ( x + y ) = x
x + ( x · y ) = x

Commutative property

x · y = y · x
x + y = y + x

Associate Property

x · ( y · z ) = ( x · y ) · z
x + ( y + z ) = ( x + y ) + z

Distributive Property

x · ( y + z ) = ( x · y ) + ( x · z )
x + ( y · z ) = ( x + y ) · ( x + z )


Rules for elementary algebra part - II:


Properties of negation

a ( -1 ) = -a

-( -a ) = a

( -a ) b = - ( ab ) = a ( -b )

( -a ) ( -b ) = ab

-( a + b ) = ( -a ) + ( -b )

Properties of equality

If a + c = b + c, then a = b

Tuesday, March 19, 2013

Linear Elementary Algebra


Introduction to linear elementary algebra:

A linear elementary algebra  equation is constructed by constants and one or more variables by using only the arithmetic operations like, addition, subtraction, multiplication and division.

The linear equations are most often used in linear elementary algebra.

A general form with two variables x and y is

y= mx +c

Where, m and b values are constants.


Example problem for linear elementary algebra 1


Example problem for linear elementary algebra 1 is given below:

Find four different solutions of the linear equation x + 2y = 6.

Solution:

x = 2, y = 2 is a solution because for x = 2, y=2

x + 2y = 6, 2 + 2(2) = 6, 2+4=6, 6=6.

Now, let us choose x = 0. With this value of x, the specified equation reduces to 2y = 6, which has the unique solution y = 3.

So x = 0, y = 3 is also a solution of x + 2y = 6.

Similarly, plug y = 0, the given equation reduces to x = 6.

So, x = 6, y = 0 is a solution of x + 2y = 6 as well.

Finally, let us take y = 1.

The given equation now reduces to x + 2 = 6, whose solution is given by x = 4. Then, (4, 1) is also a solution of the given equation so four of the infinitely many solutions of the given linear equation are:

(2, 2), (0, 3), (6, 0) and (4, 1).

Example problem for linear elementary algebra 2:


Example problem for linear elementary algebra 2 is given below:

The price of 2 pencils and 3 erasers is Rs 9 and the price of 4 pencils and 6 erasers is Rs 18. Find the price of each pencil and each eraser.

Solution:

The pair of linear equations formed was:

2x + 3y = 9 ……………..… (1)

4x + 6y = 18 …………….... (2)

We first write the value of x in terms of y from the equation

2x + 3y =9, to get x = (9-3y)/2 ………………. (3)

Now we plug this value of x in Equation (2),

4(9-3y)/2+ 6y = 18

18 – 6y + 6y = 18

18 = 18

This statement is true for all values of y.

However, there is no specific value for y as a solution.

Therefore, we cannot get a specific value of x.

Therefore, Equations (1) and (2) have infinitely lots of solutions.

Here an exact cost of a pencil and an eraser  can't be found, because there are many common solutions, to the given situation.

Friday, March 1, 2013

Elementary Algebra


Introduction to elementary Algebra

In elementary level the childrens would reading the lessons and solve their  algebra math problems with help of  simple arithmetic functions like addition,subtraction,division and multiplications and these can be denoted by (+ ,`xx` ,`-` ,÷ ).This elementary level of reading the algebra is the growing stage for the childrens in their  education field.Let we see about the problem based on elementary algebra. I like to share this help with algebra 2 problems with you all through my article.



Elementary Algebra solved problems

Problem 1:

Solve the given problem 20x - 6 = 12
Solution:

Step 1: Given that 20x - 6 =12

Step 2: Here we are going to add the 6 on both the sides

Step 3: 20x  - 6 + 6  = 12+ 6

Step 4 : 20x =18

Step 5: X = `18/20`

X = 0.9

So the solution foe x  is  0.9

Problem 2:

Calculate and simplify the given problem
6d2 + 48da

Solution:

Step 1: 6d2 + 48d

Step 2: We will take the 8a as common from 6d2 and 48d

Step 3: Then the expression become as,

6d (d + 8)

The answer: 6d2 + 48d = 6a (a + 8)

Problem 3:

solve  ` (3/2)` + `(6/2)`

Solution:

Step 1: Take LCM as 2
Step 2: = ` (3/2)` + `(6/2)`

Step 3:  Add the above terms.
= `(12+6) / 2`
= `18/2`

The answer is = `18/2`


One more solved problemsElementary Algebra


Problem 4:

Calculate and find the  system of equation 8x + 10y = 12, y = 2
Solution:

Given that:

Step 1: 8x + 10y = 12, y = 2

In the problem the y value is mentioned as 2 ,So apply the y value in 8x + 10y = 12

Step 2: 8x + 10y = 12

Step 3: 8x + 10(2) = 12

Step 4: 8x + 20 = 12

x =1

We get a variables as x =1 and y = 2.

So the answer is x =1 and y = 2.

The above solved problems done in basic elementary algebra for the childrens used in elementary. Please express your views of this topic How to Rationalize the Denominator by commenting on blog.


Practice problems in Elementary Algebra


Problem 1:

Solve the given problem 30x - 8 = 12
Answer:  X = 0.66

Problem 2:

Calculate and simplify the given problem
5d2 + 45da

Answer: 5a (a + 9)

Problem 3:

solve  ` (6/2)` + `(5/2)`

Answer:  = `22/2`



Monday, February 25, 2013

Essentials of Elementary Algebra


Introduction: Essentials of elementary algebra:

Algebra is a branch of mathematics is use to construct the mathematical model of the real-world situations and to handle the problems that we could not solve the problems using the simple arithmetic. Using the words, algebra uses symbols to make statements.

Algebra includes real numbers, complex numbers, matrices, vectors etc. In algebra, we are frequently using the letters for represents the numbers in mathematics.  Algebra is using the symbols as arithmetic operations for adding, subtracting, dividing and multiplying. I like to share this Distributive Property Definition with you all through my article.



Properties used in elementary algebra.


1. Commutative Property of Addition in algebra

The two numbers are adding any order (a, b or b, a), the sum value is the same.

a + b = b + a

2. Commutative Property of Multiplication in algebra

The two numbers are multiplying any order (a, b or b, a), the sum value is the same.

a * b = b * a

3. Associative Property of Addition in algebra

The associative property will take up three or more numbers. The parenthesis indicates the terms that are measured one unit. Hence, the numbers are 'associated' jointly. In multiplication, the product is at all times the same anyway of their grouping.

(a + b) + c = a + (b + c)

4. Associative Property of Multiplication

The associative property will take up three or more numbers. The parenthesis indicates the terms that are measured one unit. Hence, the numbers are 'associated' jointly. In addition, the sum is at all times the same anyway of their grouping.

(a * b) * c = a * (b * c)

Understanding Multiplying with Decimals is always challenging for me but thanks to all math help websites to help me out.

Example Algebraic Problem:


Example on elementary algebra:

-3(x + 7) = x + 7

Solution:
multiply factors in left term

-3x - 21 = x + 7

add 21 to both sides

-3x - 21 + 21 = x + 7 + 21

Group like terms

-3x = x + 28

subtract x to both sides

-3x - x = x + 28 -x

Group like terms

-4x = 28

multiply both sides by -1/4

x = -7

Check the solution

Left side:-3(-7 +7) = 0
right side:-7 + 7 = 0

Conclusion

x = -7 is the correct solution for the given algebraic  equation.

Saturday, February 23, 2013

Elementary Algebra Made Easy


Introduction to elementary algebra made easy:

Algebra is the branch of mathematics deals with the study of rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. It deals with the general statements of relations, utilizing letters and other symbols to represent specific sets of numbers, values, vectors, etc., in the description of such relations. Looking out for more help on What is a Common Factor in algebra by visiting listed websites.

Elementary algebraic expressions made easy:

An expression in an elementary algebra is a grouping of numbers, variables, constants, operators and parentheses or grouping brackets that are stated as an entity. An equation consists of an expression on each area of the equals sign. Some expressions are made up of sub-expressions. Much of an elementary algebra concerns simplify expressions to facilitate the solution of equations.


Steps for simplify elementary algebra expressions made easy:


Step 1: Group the terms containing the same variable together in algebra expressions.

Step 2: Perform the operation inside the parentheses for the variable and other.

Step 3: Rewrite the expressions and simplifying the algebra expressions.

Step 4: To check the equation, if there is able to simplify the expression, then repeat the step 1 to 4.

Introduction for elementary algebra equation:

An algebra equation is a mathematical statement that asserts the equality of two expressions. Elementary algebra equations consist of the expressions that are to be equal on opposite sides of an equal sign, as in

x+3=5

One use of an elementary algebra equation is in mathematical identities, assertions that are true independent of the values of any variables contained within them. Between, if you have problem on these topics What is an Dependent Variable, please browse expert math related websites for more help on cbse 11 syllabus.


Fundamental Laws of addition in elementary algebra made easy:


For the addition of positive and negative number, the following rules, established in the First Course, apply make easy to solve the an elementary algebra equation:

A number represented by a letter is called a literal number, and any number expression in which one or more number symbols are letter is called a literal expression.

Laws for addition in elementary algebra made easy:

1) To add two numbers with like signs, find the sum of their absolute values, and prefix the sign common to both.

2) To add two numbers with unlike signs, find the difference of their absolute values, and prefix the sign of the one with the greater absolute value.

Wednesday, February 13, 2013

Elementary Algebra Homework


Introduction for elementary algebra homework:

Algebra is a branch of mathematics. Algebra plays an important role in our day to day life. The elementary algebra covers that the four basic operations such as addition, subtraction, multiplication and division In Algebra, besides numerals we use symbols and alphabets in place of unknown numbers to make a statement. Hence, elementary algebra  homework covers may be as they regarded as in extension of Arithmetic Understanding One-step Linear Equations is always challenging for me but thanks to all math help websites to help me out.


Basic rules and properties of elementary algebra homework:


•     Variables

Algebraic variables are the alphabetical characters which can be used for assigning the value. While solving the algebraic equation value of that variable will be changed. Widely used variables are x, y, z

•     Constant

An algebraic constants are the value whose value are never to be changed during the solving the algebraic equation. In 2y + 5, the value 5 is the constant.

•     Expressions

An algebraic Expression is the combination of that variables, constant, coefficients, exponents, terms which are combined by the following arithmetic operations Addition, subtraction, multiplication and division. The example of an algebraic expression is given below

2y + 5

•     Term

Terms of the algebraic expression is concatenated to the form of a algebraic expression by the arithmetic operations such as addition, subtraction, multiplication and division. In the following example 3n2 + 2n the terms 3n2, 2n are combined to form the algebraic expression 3n2 + 2n by the addition operation (+)

•     Coefficient

The coefficient of an algebraic expression has the value will present just before the terms. From the following example, 3n2 + 2n the coefficient of 3n2 is 3 and 2n is 2

•     Equations

An algebraic equation equals the numbers or expressions. Most probably algebraic equation is used for that an value of the variable. The example of the equation is given below

2y + 5=0

In elementary algebra, we list out the fundamental rules and properties of pre-algebra and give examples on they may be used.

Suppose that the a, b and c are variables or pre-algebraic expressions.

Suppose that the a, b and c are variables or pre-algebraic expressions.

1. Commutative Property of Addition In elementary algebra.

a + b = b + a

Examples:

1. real numbers

2 + 3 = 3 + 2

2. pre-algebra expressions

x 2 + x = x + x 2

2. Commutative Property of Multiplication In the elementary algebra.

a * b = b * a

Examples:

1. real numbers

5 * 7 = 7 * 5

2. pre-algebra expressions

(x 3 - 2) * x = x * (x 3 - 2)

3. Associative Property of Addition In elementary algebra.

(a + b) + c = a + (b + c)

Having problem with Variables and Expressions keep reading my upcoming posts, i will try to help you.


Order of the operation for elementary algebra homework


1. Reduce whatever inside the parentheses.

2. Reduce the exponents.

3. Multiplication or division.

4. Finally, perform Addition or Subtraction.

Examples of elementary algebra home work

Elementary algebra homework problem1:

5*(10+5)

Solution:

5*(10+5) = 5*10+5*5

=50+25

=75

Elementary algebra homework problem 2:

2+(4+6)

Solution:

2+(4+6)=2+10

=12

Elementary algebra homework problem 3: Find the value for the below expression if a=6

3(a-9)

Solution:

= 3(a-9) (evaluate the expression at inside the parenthesis)

= 3(6-9)

= 3(-3) which is equal to 3 * -3

= -9

Elementary algebra homework problem 4:

Simplify the following expression 4*(44÷2)

Solution:

= 4*(44÷2) (evaluate the expression inside the parenthesis)

= 4*(22)

= 88

Elementary algebra homework problem5:

Simplify the following expression 3*(27÷9)+5

Solution:

= 3*(27÷9)+5 (evaluate the expression inside the parenthesis)

= (3*3) +5

= 9+5

= 14